The half-life of radioactive Polonium `(Po)` is `138.6` days. For ten lakh Polonium atoms, the number of disintegrations in `24` hours is

Options

A. 2000
B. 3000
C. 4000
D. 5000

Answer

D

Explanation

(d) `n = (24)/(24 xx 138.6) = (1)/(138.6)`
Now `(N)/(N_0) = ((1)/(2))^n = ((1)/(2))^(1//138.6)`
`rArr N = 10,00000((1)/(2))^(1//138.6) = 995011`
So number of disintegration.