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A radioactive nucleus undergoes alpha-em...

A radioactive nucleus undergoes `alpha-`emission to form a stable element. What will be the recoil velocity of the daughter nucleus is `V` is the velocity of `alpha`-emission and `A` is the atomic mass of radioactive nucleus ?

A

`(4 V)/(A - 4)`

B

`(2 V)/(A - 4)`

C

`(4 V)/(A + 4)`

D

`(2 V)/(A + 4)`

Text Solution

Verified by Experts

The correct Answer is:
A

(a) According to conservation of momentum
`4 v = (A - 4) v' rArr v' = (4v)/(A - 4)`.
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