A radioactive nucleus is being produced at a constant rate `alpha` per second. Its decay constant is `lamda`. If `N_0` are the number of nuclei at time `t = 0`, then maximum number of nuclei possible are.

Options

A. `(alpha)/(lamda)`
B. `N_0 + (alpha)/(lamda)`
C. `N_0`
D. `(lamda)/(alpha) + N_0`

Answer

A

Explanation

(a) Maximum number of nuclei will be present when rate of decay = rate of formation `rArr lamda N = alpha rArr N = (alpha)/(lamda)`.