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A nucleus .ZX^A emits 9 alpha-particles ...

A nucleus `._ZX^A` emits `9 alpha-`particles and `5p` particle. The ratio of total protons and neutrons in the final nucleus is.

A

`((Z - 13))/((A - Z - 23))`

B

`((Z - 18))/((A - 36))`

C

`((Z - 13))/((A - 36))`

D

`((Z - 13))/((A - Z - 13))`

Text Solution

Verified by Experts

The correct Answer is:
A
(a) `._Z X^A overset (9alpha)rarr ._(Z-18) X^(A -36) overset (5 beta)rarr ._(Z-13)X^(A-36)`
Number of protons `= (Z = 13)`
Number of neutrons `=(A - 36) - (Z - 13)=(A - Z -23)`
` :. (P)/(N) = ((Z - 13))/((A - Z-23))`.
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Knowledge Check

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