`U^238` decays into `Th^234` by the emission of an a-particle. There follows a chain of further radioactive decays, either by `alpha`-decay or by `beta-`decay. Eventually a stable nuclide is reached and after that, no further radioactive decay is possible. which of the following stable nuclides is the end product of the `U^238` radioactive decay chain ?

Options

A. `Pb^206`
B. `Pb^207`
C. `Pb^208`
D. `Pb^209`

Answer

A

Explanation

(a) `(4n + 2)` series starts from `U^238` and its stable end product if `Pb^206`.