In the reaction `._1^2 H + ._1^3 H rarr ._2^4 He + ._0^1 n`, if the binding energies of `._1^2 H, ._1^3 H` and `._2^4 He` are respectively `a,b` and `c` (in MeV), then the energy (in MeV) released in this reaction is.

Options

A. `c + a - b`
B. `c - a - b`
C. `a + b + c`
D. `a + b - c`

Answer

B

Explanation

(b) During fusion binding energy of daughter nucleus is always greater than the total energy of the parent nuclei so energy released `= c - (a + b) = c - a - b`.