A potential barrier of `0.50 V` exists across a `P-N` junction. If the depletion region is `5.0xx10^(-7)m`, wide the intensity of the electric field in this region is

Options

A. `1.0xx10^(6) V//m`
B. `1.0xx10^(5) V//m`
C. `2.0xx10^(5)V//m`
D. `2.0xx10^(6) V//m`

Explanation

To find the intensity of the electric field in the depletion region of a P-N junction, we can use the formula for electric field intensity (E):

\[ E = \frac{V}{D} \]

where:
- \( E \) is the electric field intensity,
- \( V \) is the potential difference (or potential barrier),
- \( D \) is the width of the depletion region.

### Step 1: Identify the given values
- Potential barrier \( V = 0.50 \, \text{V} \)
- Width of the depletion region \( D = 5.0 \times 10^{-7} \, \text{m} \)

### Step 2: Substitute the values into the formula
Now, we can substitute the given values into the formula for electric field intensity:

\[ E = \frac{0.50 \, \text{V}}{5.0 \times 10^{-7} \, \text{m}} \]

### Step 3: Perform the calculation
Calculating the above expression:

\[ E = \frac{0.50}{5.0 \times 10^{-7}} = 1.0 \times 10^{6} \, \text{V/m} \]

### Step 4: Write the final answer
Thus, the intensity of the electric field in the depletion region is:

\[ E = 1.0 \times 10^{6} \, \text{V/m} \]