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The diode shown in the circuit is a sili...

The diode shown in the circuit is a silicon diode. The potential difference between the points `A` and `B` will be

A

`6 V`

B

`0.6V`

C

`0.7 V`

D

`0V`

Text Solution

Verified by Experts

The correct Answer is:
A
In the given condition diode is in reverse biasing so it acts as open circuit. Hence potential difference between `A` and `B` is `6V`.
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