Logic gates `X` and `Y` have the truth tables shown below

`|(P,Q,R,P,R),(0,0,0,0,1),(1,0,0,1,0),(0,1,0,,),(1,1,1,,)|`
When the output of `X` of connected to the input of `Y`, the resulting combination is equivalent to a single.

Options

A. `NOT`gate
B. `OR` gate
C. `NAND` gate
D. `AND` gate

Answer

C

Explanation

The truth table of the resulting logic circuit by connecting `X` of `Y` is as follows
`|(P,Q,R,R),(0,0,0,1),(1,0,0,1),(0,1,0,1),(1,1,1,0)|`
Hence, from the truth table, the combination is equivalent to a single `NAND` gate. (`OR X` is an `AND`gate and `Y` is a `NOT` gate, thus the combination is `NOT AND` gate, i.e., a `NAND` gate)