The circuit is equivalent to

Options

A. `AND` gate
B. `NAND` gate
C. `NOR` gate
D. `OR` gate

Answer

C

Explanation

The gate circuit can be shown by giving two inputs `A` and `B`

Output of `NOR` gate, `Y_(1)=bar(A+B)`
Output of `NAND`gate,
`Y_(2)=bar(Y_(1).Y_(1))=bar(bar(A+B).bar(A+B))=bar(bar(A+B))+bar(bar(A+B))`
`=(A+B)+(A+B)`
`=A+B`
Output of `NOT` gate, `Y=bar(Y)_(2)=bar(A+B)`
Which is the output of `NOR` gate.
Alternative: