The input resistance of a silicon transistor is `100 Omega`. Base current is changed by `40 muA` which results in a change in collector current by `2 mA`. This transistor is used as a common-emitter amplifier with a load resistance of `4k Omega`. The voltage gain of the amplifier is

Options

A. `2000`
B. `3000`
C. `4000`
D. `1000`

Answer

A

Explanation

We know `V_(g)=beta(R_(L))/(R_(i))=(DeltaI_(C))/(DeltaI_(B)) (R_(L))/(R_(i)) ( :' beta=(DeltaI_(C))/(DeltaI_(B)))`
On putting given values
`V_(g)=(2xx10^(-3))/(40xx10^(-6))xx(4xx10^(3))/100=2000`