In order to obtain an output `Y=1` form the circuit of fig. the inputs must be

Options

A. `A=1,B=0,C=0`
B. `A=1,B=0,C=1`
C. `A=1,B=1,C=0`
D. `A=0,B=1,C=0`

Answer

B

Explanation

Here `Y=(A+B).C`
`|(A,B,C, Y=(A+B).C),(0,0,0,0),(1,0,0,0),(0,1,0,0),(0,1,0,0),(0,1,1,1),(1,0,1,1),(1,1,1,1)|`
`C` should be `1` either `A` and `B` or both `A` and `B` are `1`.
therefore, `A=1,B=0,C=1`