In the following common emitter configuration an `NPN` transistor with current gain `beta=100` is used. The output voltage of the amlifier will be

Options

A. `10 mV`
B. `0.1 V`
C. `10 V`
D. `1.0 V`

Answer

D

Explanation

Current gain is deffined as the ratio of collector current to base current, that is
`beta=(i_(C))/(i_(B))=(V_(o))/(V_(i))`
Where `V_(o)` is output voltage and `V_(i)` is input voltage.
Given `beta=100,V_(i)=10^(-2)V`
`:. V_(o)=betaV_(i)=100xx10^(-2)=1V`