Consider an `n-p-n` transistor amplifer in common-emitter configuration. The current gain of the transistor is `100`. If the collector current changes by `1mA`, what will be the change in emitter current?

Options

A. `1.01 mA`
B. `1.1 mA`
C. `0.01 mA`
D. `10 mA`

Answer

A

Explanation

Current gain `=(chang e i n coll ect or current)/(chang e i n base current)`
`beta=(Deltai_(C))/(Deltai_(B))`
Also `i_(E)=i_(B)+i_(C) implies Deltai_(E)=Deltai_(B)+Deltai_(C)`
`beta=(Deltai_(C))/(Deltai_(E)-Deltai_(C))`
Given, `beta=100,Deltai_(C)=1mA`
`:. 100=1/(Deltai_(E)-1), Deltai_(E)-1=1/100=0.01`
`Deltai_(E)=1+0.01=1.01 mA`