Reverse bias applied to a junction diode

Options

A. no current flow
B. the depletion region is reduced
C. the height of the potential barrier is reduced
D. the depletion region is increased

Answer

D

Explanation

In reverse biasing, the applied voltage `V` on the `n`-side is positive and is negative on the `P` -side. The applied biase `V` and the barrier potential `V_(B)` are in the same direction making the effective junciton potential `V+V_(B)`. As a result, the junction width will increases. the higher junction potential would restrict the flow of majority carriers to a much greater extent. However, such a field will favour the flow of minority carriers. So, reverse biase current will be due to the minority carriers only