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A light emitting diode (LED) has a volta...

A light emitting diode `(LED)` has a voltage drop of `2V` across it and passes a current of `10 mA`. When it operates with a `6V` battery through a limiting resistor `R`. The value of `R` is

A

`400 Omega`

B

`4 k Omega`

C

`200 Omega`

D

`40 k Omega`

Text Solution

Verified by Experts

The correct Answer is:
A
The term `'LED'` is abbreviated as 'Light Emitting Diode'. It is forward-biased `p-n`-junction which emits spontaneous radiation. Current in the circuit `=10 mA =10xx10^(-3) A` and voltage in the circuit `=6-2=4V`
From Ohm's law.
`V=IR`
`:. R=V/I=4/(10xx10^(-3))=400 Omega`
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