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For the transistor circuit shown below, ...

For the transistor circuit shown below, if `beta=100`, voltage drop between emitter and base is `0.7V` then value of `V_(CE)` will be

A

`10 V`

B

`5 V`

C

`13 V`

D

`0 V`

Text Solution

Verified by Experts

The correct Answer is:
C
`i_(b)=(5-0.7)/8.6=0.5 mA`
`implies I_(c)=betaI_(b)=100xx0.5 mA`
By using
`V_(CE)=V_(C C)-I_(C)R_(L)=18-50xx10^(-3)xx100=13V`
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