For a transistor ampliflier in common em...

For a transistor ampliflier in common emiter configuration for load imperdance of `1 k Omega (h_(fe) = 50 and h_(oe) = 25)` the current gain is

`-5.2`

`-15.7`

`-24.8`

`-48.78`

Text Solution

Verified by Experts

The correct Answer is:

In common emitter configuration current gain
`A_(1)=(-h_(fe))/(1+h_(oe)R_(L))=(-50)/(1+25xx10^(-6)xx10^(3))=-48.78`.

Topper's Solved these Questions

SEMICONDUCTOR ELECTRONICS
A2Z|Exercise SECTION -D|1 Videos
NUCLEAR PHYSICS
A2Z|Exercise Section D - Chapter End Test|29 Videos
SOURCE AND EFFECT OF MAGNETIC FIELD
A2Z|Exercise Section D - Chapter End Test|30 Videos

Similar Questions

Explore conceptually related problems

For a transistor amplifier in common emitter configuration for load impendance of 1k Omega(h_(fe)-50 and h_(oe)=25 muA//V) the current gain is

For a transistor amplifier in common emitter configuration for load impedance of 1 k Omega. (h_(fe) = 50 and h_(oe) = 25 xx 10^(-6)) the current gain is

A transistor connected at common emitter mode contains load resistance of 5 k Omega . If the input peak voltage is 5 mV and the current gain is 50, find the voltage gain.

The current gain for a transistor used in common - emitter configuration is 98. If the load resistance be 1 M Omega and the internal resistance be 600Omega , what is the voltage gain ?

For a transistor is common base configuration if beta is 100 , the value of current gain is is

Consider an n-p-n transistor amplifer in common-emitter configuration. The current gain of the transistor is 100 . If the collector current changes by 1mA , what will be the change in emitter current?

For a transistor in common emitter configuration, the voltage drop across the load of 1000 Omega is 0.5 V. If the value of alpha for the transistor is 0. 98, then the base current will be approximately equal to

If the current amplification factor for a transistor connected in common emitter configuration is 100 and input resistance is 200 Omega , then the power gain is (Assume output resistance is 0.8 kOmega )

Current gain of common base configuration of a transistor is 0.9. It is used in common emitter configuration. Input and output resistances are 0.6k Omega , 50k Omega respectively. Find power gain.

A2Z-SEMICONDUCTOR ELECTRONICS-EXERCISE

When forward bias is applied to a P-N junction, then what happence to ...
Text Solution
|
When npn transistor is used as an amplifler
Text Solution
|
For a transistor ampliflier in common emiter configuration for load im...
Text Solution
|
If a full wave reactifier circuit is operating from 50 Hz mains, the f...
Text Solution
|
In a common base ampifier , the phase difference between the input sig...
Text Solution
|
To obtain a P-type Si semiconductor, we need to dope pure Si with
Text Solution
|
Two PN-junction can be connected in series by three different methods ...
Text Solution
|
In a p- n junction diode not connected to any circuit,
Text Solution
|
Which of the following statements is not true?
Text Solution
|
The dominant mechanisms for motion of charge carriers in forward and r...
Text Solution
|
For a given plate voltage , the plate current in a triode valve is max...
Text Solution
|
The probbility of electrons to be found in the conduction band of an i...
Text Solution
|
The typical ionisation energy of a donor in silicon is
Text Solution
|
In the circuit given below, V(t) is the sinusoidal voltage source, vol...
Text Solution
|
The circuit shown in following figure contanis two diode D(1) and D(2)...
Text Solution
|
The following configuration of gate is equivalent to
Text Solution
|
The output of a NAND gate is 0
Text Solution
|
We are accustomed to decinnial form of stating numbers. For example 12...
Text Solution
|
Given below are four logic tage symboles. Those for OR, NOR and NAND a...
Text Solution
|
Consider a two -input AND gate of figure. Out of the four entries for ...
Text Solution
|