The circuit shown in following figure contanis two diode `D_(1)` and `D_(2)` each with a forward resistance of `50 ohm` and with infinite backward resistance. If the battery voltage is `6V`, the current through the `100` ohm resistance (in amperes) is

Options

A. Zero
B. `0.02`
C. `0.03`
D. `0.036`

Answer

B

Explanation

According to the given polarity, diode `D_(1)` is forward biased while `D_(2)` is reverse biased. Hence current will pass through `D_(1)` only.
So current `i=6/((150+50+100))=0.02 A`