A radio receiver antenna that is `2 m` long is oriented along the direction of the electromagnetic wave and receives a signal of intensity `5xx10^(-16) W//m^(2)`. The maximum instaneous potential difference across the two ends of the antenna is

Options

A. `1.23 muV`
B. `1.23 mV`
C. `1.23 V`
D. `12.3 mV`

Answer

a

Explanation

`I=(1)/(2)epsilon_(0)CE_(0)^(2)`
`rArr E_(0)=sqrt((2I)/epsilon_(0C))=sqrt((2xx5xx10^(-16))/(8.85))=0.61xx10^(-6)(V)/(m)` Also `E_(0)=(V_(0))/(d) rArrV_(0)=E_(0)d=0.61xx10^(-6)xx2=1.23muV`