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The intensity of gamma radiation from a ...

The intensity of gamma radiation from a given source is `I`
On passing through `36 mm` of lead , it is reduced to `(1)/(8)` . The thickness of lead which will reduce the intensity to `(1)/(2)` will be

A

`18mm`

B

`12mm`

C

`6mm`

D

`9mm`

Text Solution

Verified by Experts

The correct Answer is:
B
`I' =Ie^(-mu x)rArr x=(1)/(mu)"log"_(e)(I)/(I')`
(where I = original intensity, I= changed intensity)
`36=(1)/(mu) "log"_(e) (I)/(I//8)=(3)/(mu) "log"_(e)2`
`x=(1)/(mu)"log"_(e) (I)/(I//2)=(1)/(mu)"log"_(e)2`
From equation (i) and (ii), `x=12mm`.
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