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The average value of electric energy den...

The average value of electric energy density in an electromagnetic wave is (`E_(0)` is peak value):

A

`(1)/(2)epsilon_(0)E_(0)^(2)`

B

`(E_(0)^(2))/(2epsilon_(0)`

C

`epsilon_(0)E_(0)^(2)`

D

`(1)/(4)epsilon_(0)E_(0)^(2)`

Text Solution

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The correct Answer is:
To find the average value of electric energy density in an electromagnetic wave, we can follow these steps: ### Step 1: Understand the formula for electric energy density The electric energy density (u_E) in an electromagnetic wave is given by the formula: \[ u_E = \frac{1}{2} \epsilon_0 E^2 \] where: - \( \epsilon_0 \) is the permittivity of free space (approximately \( 8.85 \times 10^{-12} \, \text{F/m} \)), - \( E \) is the electric field strength. ### Step 2: Use the peak value of the electric field In this case, we are given that \( E_0 \) is the peak value of the electric field. Therefore, we will substitute \( E \) with \( E_0 \) in the formula: \[ u_E = \frac{1}{2} \epsilon_0 E_0^2 \] ### Step 3: Calculate the average value The average electric energy density over one complete cycle of the electromagnetic wave can be expressed as: \[ \langle u_E \rangle = \frac{1}{2} \epsilon_0 E_0^2 \] This expression represents the average value of the electric energy density in the wave. ### Final Result Thus, the average value of electric energy density in an electromagnetic wave is: \[ \langle u_E \rangle = \frac{1}{2} \epsilon_0 E_0^2 \] ---

To find the average value of electric energy density in an electromagnetic wave, we can follow these steps: ### Step 1: Understand the formula for electric energy density The electric energy density (u_E) in an electromagnetic wave is given by the formula: \[ u_E = \frac{1}{2} \epsilon_0 E^2 \] where: ...
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Knowledge Check

  • The peak value of the electric field component of an electromagnetic wave is E. At a particular instant the intensity of the wave is of 0.020 W//m^(2) . If the electric field were increased to 5E what would be the intensity of the wave ?

    A
    `0.020 W//m^(2)`
    B
    `0.25 W//m^(2)`
    C
    `0.10 W//m^(2)`
    D
    `0.50 W//m^(2)`
  • In electromagnetic waves there is zero average value for

    A
    electric field intensity
    B
    magnetic field intensity
    C
    electric field energy
    D
    magnetic field energy
  • Calculate the average total energy density of an electromagnetic wave coming from the sun that has the RMS value of electric field as 720NC^(-1)

    A
    `3.3xx10^(-3)Jm^(-3)`
    B
    `4.58xx10^(-6)Jm^(-3)`
    C
    `6.37xx10^(-9)Jm^(-3)`
    D
    `81.35xx10^(-12)Jm^(-3)`
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