The transmitting antenna of a radio-station is mounted verticlly. At a point electric field is 10Km1 due north of the treansmitter the peak electric field is `10^(-3) "volt"//m` meter. The amplitude of the radiated magnetic magnetic field is:

Options

A. `3.33xx10^(-10) tesla`
B. `3.33xx10^(-12) tesla`
C. `10^(-3) tesla`
D. `3xx10^(5) tesla`

Answer

b

Explanation

`B_(0)=(E_(0))/(c)=(10^(-3))/(3xx10^(8))=3.3xx10^(-12)T`