The maximum peak ro peak voltage of an AM wire is `24 mV` and the minimum peak to peak voltage is `8mV`. The modulation factor is

Options

A. `10%`
B. `20%`
C. `25%`
D. `50%`

Answer

d

Explanation

Here, `V_(max)=(24)/(2)=12mV` and `V_(min)=(8)/(2)=2mV`
Now,
`m=(V_(max)-V_(min))/(V_(max)+V_(min))=(12-4)/(12+4)=(8)/(16)=(1)/(2)=0.5=50%`