Consider an optical communication system operating at `lambda=800 nm`. Suppose, only `1%` of the optical source frequency is the available channel bandwidth for optical communication. How many channels can be accommondated for transmitting audio signals requiring a bandwidth of `8kHz`

Options

A. `4.8xx10^(8)`
B. `48`
C. `6.2xx10^(8)`
D. `4.8xx10^(5)`

Answer

a

Explanation

Optical source frequency `f=(c)/(lambda)`
`=3xx10^(8)//(800xx10^(-9))=3.8xx10^(14)Hz`
Bandwidth of channel (`1%` of above) `=3.8xx10^(12)Hz`
Number of channels = (Total bandwidth of channel )/(Bandwidth needed per channel)
`implies` Number of channels for audio signal
`=(3.8xx10^(12))//(8xx10^(3))=4.8xx10^(8)`