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A transmitter supplies 9 kW to the aeria...

A transmitter supplies `9 kW` to the aerial when unmodulated. The power radiation when modulated to `40%` is

A

`5 kW`

B

`9.72 kW`

C

`10 kW`

D

`12 kW`

Text Solution

Verified by Experts

The correct Answer is:
b
`P_(t)=P_(c)[1+(m^(2))/(2)]=9[1+((0.4)^(2))/(2)]`
`=9[1+(0.16)/(2)] ( :. M=40%=0.4)`
`=9(1.08)=9.72 kW`
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