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An AM wave has 1800 watt of total power ...

An AM wave has `1800` watt of total power content, For `100%` modulation the carrier should have power content equal to

A

`1000` watt

B

`1200` watt

C

`1500` watt

D

`1600` watt

Text Solution

Verified by Experts

The correct Answer is:
B
`P_(t)=P_(c)(1+(m_(a)^(2))/(2))`, Here `m_(a)=1`
`implies 1800=P_(c)(1+((1)^(2))/(2))impliesP_(c)=1200W`
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