A radiation of energy `E` falls normally on a perfctly refelecting surface . The momentum transferred to the surface is

Options

A. `(E)/(C)`
B. `(2E)/(C)`
C. `(2E)/(C^(2))`
D. `(E)/(C^(2))`

Answer

b

Explanation

Momentum of light falling on reflecting surface
`P=(E)/(C)`
As surface is perfectly so momentum reflect `P'=-(E)/(C )`

So momentum transferred
`P-P'=(E)/(C)-(-(E)/(C))=(2E)/(C)`