An amplitude modulated wave is modulated to `50%`. What is the saving in power if carrier as well as one of the side band are suppressed?

Options

A. `70%`
B. `65.4%`
C. `94.4%`
D. `25.5%`

Answer

c

Explanation

`P_(sb)=P_(c)((m_(a))/(2))^(2)=P_(c)((0.5)^(2))/(4)=0.0625P_(c)`
Also `P=P_(c)(1+(m_(a)^(2))/(2))=P_(c)(1+((0.5)^(2))/(2))=1.125P_(c)`
`:. %` saving `=((1.125P_(c)-0.0625P_(c)))/(1.125P_(c))xx100=94.4%`.