A plane electromagnetic wave of wave intensity `6 W//m^(2)` strikes a small mirror of area `40cm(2)`, held perpendicular to the approaching wave. The momentum transferred by the wave to the mirror each second will be

Options

A. `6.4xx10^(-7) kg-m//s^(2)`
B. `4.8xx10^(-8) kg-m//s^(2)`
C. `3.2xx10^(-9) kg-m//s^(2)`
D. `1.6xx10^(-10) kg-m//s^(2)`

Answer

D

Explanation

Momentum transferred in one second
`P=(2U)/(c)=(2S_(av)A)/(c)=(2xx6xx40xx10^(-4))/(3xx10^(8))`
`=1.6xx10^(-10)kg-m//s^(2)`.