The solubility of `Sr(OH)_(2)` at `298 K` is `19.23 g L^(-1)` of solution. Calculate the concentrations cf strontium and hydroxyl ions and the `pH` of the solution.

Explanation

`Sr(OH)_(2)rarr Sr^(2+)+2OH^(-)`
`[Sr(OH)_(2)]=(19.23)/(121.62xx1)=0.158M`
`:. [OH^(-)]= 2xx0.158M= 0.316M`
or `pOH=0.5003`
`:. pH= 13.4997`
`[Sr^(2+)]=0.158M`