`M(OH)_(x)` has `K_(SP)=4xx10^(-12)` and its solubility in water is `10^(-4)` M. Calculate the value of x.

Explanation

`M(OH)_(x)hArr underset(S)(M^(x+))+underset(XS)(XOH^(-))`
`K_(SP)=S.(XS)^(x)` , `("Give" S= 10^(-4))`
or `4xx10^(-12)=10^(-14). (X.10^(-4))^(x)`
`10^(-4)xx10^(-4x).X^(x)=4xx10^(-12)`
`X^(x).(10^(-4))^(1+x)=4xx10^(-12)`
`:. X=2`