What will be the resultant pH, when 200 mL of an aqueous solution of `HCI(pH=2.0)` is mixed with 300 mL of an aqueous solution of `NaOH(pH=12.0)` ?

Explanation

`pH of HCI = 2 :. [HCI]= 10^(-2)M`
`pH of NaOH = 12 :. [NaOH] = 10^(-2)M`
`{:(,HCI+,NaOHrarr,NaCI+,H_(2)O),("Meq.before reaction",200xx10^(-2)=2,300xx10^(-2)=3,0,0),("Meq. after reaction,0,1,2,2):}`
`:. [OH^(-)]` left form `NaOH= (1)/(500)=2xx10^(-3)M`
`:. pOH= -log OH^(-)= -log 2xx10^(-3)`
`:. pOH = 2.6989`
`:. pH= 11.3010`