Both `[Ni(CO)_4]` and ` [Ni (CN)_4]^(2-) ` are diamagnetic The hybridisations of nickel in these complexes , respectively are :

Options

A. ` sp^3 , sp^3`
B. ` sp^3 , dsp^2`
C. ` dsp^2 , sp^3`
D. `dsp^2 , dsp^2`

Answer

B

Explanation

In `[Ni(CO)_(4)], CO` is strong field ligand.

Ni in `[Ni(CO)_(4) ]`:

It is a tetrahedral complex .
In `[Ni(CN_(4)]^(2-), CN^(-)` is strong field ligand.
`Ni^(2+)` in `[Ni(CN)_(4)]^(2-)`

`:.` It is a square planar complex.