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Find the bond order of B2...

Find the bond order of ` B_2`

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` B_2=sigma1s^2,sigma^**1s^2,sigma2s^(2),sigma^**2s^2, [(pi2p_y^1),(pi2p_z^1)]`
`:.` Bond order of `B_2 1/2 xx [ 6 - 4 ] =1 `.
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Knowledge Check

  • Bond order of Be_2 is

    A
    1
    B
    2
    C
    3
    D
    0

  • The bond order of O_2 is

    A
    1
    B
    2
    C
    3
    D
    None of these

  • The bond order of N_2 is

    A
    1
    B
    2
    C
    3
    D
    None of these

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    What is meant by the term bond order ? Calculate the bond order ? Calculate the bond order of : N_(2),O_(2),O_(2)^(-)and O_(2)^(2-)

    Bond order is

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