A `100-W,110-V` incardescent lamp is connected in series with an electrolyte cell containing cadmium sulphate solution. How much cadmium will be deposited by the current flowing for `10h` ?

Explanation

Current Strength `= ("Watt")/("Volt") = (100)/(110)`
`= 0.909` ampere
Given, `t = 10 xx 60 xx 60` sec, `E_(Cd) = (112.4)/(2)`
`(Cd^(2+)+2e rarr Cd)`
`w = (E.i.t)/(96500)`
`w= (112.4 xx 0.909 xx 10 xx 60 xx 60)/(2 xx 96500) = 19.06 g`