What is the current efficiency of an electro-deposition of copper is deposited of copper metal from `CuSO_(4)` solution in which `9.80 g` copper is deposited by the passage of `5` ampere current for `2` hour?

Explanation

`(w)/(E) = (i.t)/(96500)`
`(9.8)/(63.5//2) = (i xx 2 xx 60 xx 60)/(96500)`
`i = 4.14` ampere
`:.` Current efficiency `= ("Theoretical valule of I")/("Practical value of I") xx 100`
`= (4.14)/(5) xx 100 = 82.8%`