How long a current of `3A` has to be passed through a solution of silver nitrate to coat a metal surface of `80cm^(2)` with a `0.005-mm-` thick layer ? The density of silver is `10.5g cm^(-3)`.

Explanation

Given, `i = 3` ampere
Also Volume covered by
`Ag = 80 xx 0.005 xx 10^(-1) cm^(3) = 0.04 cm^(3)`
`:.` Weight of `Ag` used `= 0.04 xx 10.5 g`
`w_(Ag) = (E.i.t)/(96500)`
`0.04 xx 10.5 = (108 xx 3 xx t)/(96500)`
`t = 125.09` sec.