The cell reaction for the given cell is spontaneoous if:
`Pt|Cl_(2)(P_1)|Cl^(-)(1M)||Cl^(-)(1M)|Pt|Cl_(2)(P_2)`

Options

A. `P_(1) gt P_(2)`
B. `P_(1) lt P_(2)`
C. `P_(1) = P_(2)`
D. `P_(2) = 1` atm

Answer

B

Explanation

`E_("cell") = E_(OP_(Cl))^(@) + E_(RP_(Cl))^(@) + (0.059)/(2)"log"([Cl^(-)]_(LHS)^(2)P_(2))/([Cl^(-)]_(RHS)^(1)P_(2)`
`= (0.059)/(2)"log"(P_(2))/(P_(1))`
`E_("cell")` is `+ve` when `P_(2)gtP_(1)`