The following facts are availabel `:`
`2A^(c-)+B_(2) rarr 2B^(-)+A_(2),`
`2C^(c-)+B_(2) rarr No reaction, `
`2D^(c-)+A_(2) rarr 2A^(c-)+D_(2)`
Which of the following statement is correct ?

Options

A. `E_(C^(-)//C_(2))^(@) gt E_(B^(-)//B_(2))^(@) gt E_(A^(-)//A_(2))^(@) gt E_(D^(-)//D_(2))^(@)`
B. `E_(C^(-)//C_(2))^(@) lt E_(B^(-)//B_(2))^(@) lt E_(A^(-)//A_(2))^(@) lt E_(D^(-)//D_(2))^(@)`
C. `E_(C^(-)//C_(2))^(@) lt E_(B^(-)//B_(2))^(@) gt E_(A^(-)//A_(2))^(@) gt E_(D^(-)//D_(2))^(@)`
D. `E_(C^(-)//C_(2))^(@) gt E_(B^(-)//B_(2))^(@) lt E_(A^(-)//A_(2))^(@) lt E_(D^(-)//D_(2))^(@)`

Answer

B

Explanation

Given examples are of non-metals. A non-metal having higher erduction potential replaces the other from its solution. Thus, `E_(RP_(D))^(@) lt E_(RP_(A))^(@) lt E_(RP_(B))^(@)` or
Thus `E_(OP_(D))^(@) gt E_(OP_(A))^(@) gt E_(OP_(B))^(@)`.
thus onlu choice is (b) because `E_(OP_(B))^(@) gt E_(OP_(C))^(@)` as `B` does not replaces `C` from solution.