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If e(Fe^(2+) //Fe)^@ =- 0. 44 1V. And E(...

If `e_(Fe^(2+) //Fe)^@ =- 0. 44 1V`. And `E_(Fe^(3+)//Fe^(2+))^(o) = 0. 771 V`. The standard emf of the reaction ` Fe +2 Fe^(3+) rarr 3Fe^(2+)` will be .

A

`1.212 V`

B

`0.111 V`

C

`0.330 V`

D

`1.653 V`

Text Solution

Verified by Experts

The correct Answer is:
A
`E_("cell") = E_(Fe//Fe^(2+))^(@) + E_(Fe^(3+)//Fe^(2+))^(@)`
`= 0.441 + 0.771 = 1.212 V`
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