For the given cell,
`underset(P_(1))(Pt,C1_(2))|underset(C_(1))(HC1)||underset(C_(2))(HC1)|underset(P_(2))(C1_(2),Pt)`
The emf will be positive when :

Options

A. `C_(1) gt C_(2)`
B. `C_(2) gt C_(1)`
C. `C_(1) = C_(2)`
D. None of these

Answer

A

Explanation

`{:(L.H.S.2Cl^(-)rarrCl_(2)+2e),(R.H.S.2e+Cl^(2)rarrunderset(C_(2))(Cl^(-))):}/(underset(C_(1))(Cl^(-))rarrunderset(C_(2))(Cl^(-)))`
Thus, `E_("cell") = -(0.059)/(1)"log"(1)/(C_(1))+(0.059)/(1)"log"(1)/(C_(2))`
`= (0.059)/(1)"log"(C_(1))/(C_(2))`
Thus, `E_("cell") = +ve` when `C_(1) gt C_(2)`