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E^(@) for F(@)+2e hArr2F^(-) is 2.7 V ...

`E^(@)` for `F_(@)+2e hArr2F^(-)` is `2.7 V`
Thus, `E^(@)` for `F^(-) hArr(1)/(2)Fe +e` is :

A

`1.35 V`

B

`-1.35 V`

C

`-2.7 V`

D

`2.7 V`

Text Solution

Verified by Experts

The correct Answer is:
C
`E^(@)` value do not depend upon stoichiometry of change but depedn upon the direction, i.e.,
`E_(OP)^(@) = -E_(RP)^(@)`.
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