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The emf of given cell Pt - underset(P(1)...

The `emf` of given cell `Pt - underset(P_(1))(H_(2))|H^(+)|underset(P_(2))(H_(2) - Pt` is :

A

`(RT)/(F)log'(P_(1))/(P_(2))`

B

`(RT)/(2F)log_(e)(P_(1))/(P_(2))`

C

`(RT)/(F)log _(e)(P_(2))/(P_(1))`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B

`underset(P_(1))(H_(2)) rarr 2H^(+) + 2e`
`2H^(+) + 2e rarr underset(P_(2))(H_(2))`
`E_(cell) = E_(OP_(H))^(@) + E_(RP_(H))^(@) + (Rt)/(2F)loge([P_(H_(2))]_(1))/([P_(H_(2))]_(2))`
`= (Rt)/(2F)log_(e)(P_(1))/(P_(2))`
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