The standard `EMF` of a galvanic cell involving cell reaction with `n=2` is found to be `0.295 V` at `25^(@)C` . The equilibrium constant of the reaction would be

Options

A. `1 xx 10^(-10)`
B. `29.5 xx 10^(-2)`
C. `10`
D. `1 xx 10^(10)`

Answer

D

Explanation

`E_(cell)^(@) = (0.059)/(n)logK_(c)`
`0.295 = (0.059)/(2)logK_(c)`
`K_(c) = 1 xx 10^(10)`