The cell , `Zn | Zn^(2+) (1M) || Cu^(2+) (1M) Cu (E_("cell")^@ = 1. 10 V)`,
Was allowed to be completely discharfed at `298 K `. The relative concentration of `2+` to `Cu^(2+) [(Zn^(2=))/(Cu^(2+))]` is :

Options

A. antilog `(24.08)`
B. `3.7.3`
C. `10^(37.3)`
D. `9.65 xx 10^(4)`

Answer

C

Explanation

`E_(cell) = E_(cell)^(@) - (0.0591)/(n)log Q`
Where, `Q = ([Zn^(2+)])/([Cu^(2+)])`
For complete discharge `E_(cell) = 0`
So `E_(cell)^(@) = (0.0591)/(2)log'Q = ([Zn^(2+)])/([Cu^(2+)])`
`:. Q = [([Zn^(2+)])/([Cu^(2+)])] = 10^(37.3)`