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The correct relationship between free en...

The correct relationship between free energy change in a reaction and the corresponding equilibrium constant `K_(c)` is:

A

`DeltaG^(@) = RT ln K_(c)`

B

`-DeltaG = RT In K_(c)`

C

`DeltaG = Rt ln K_(c)`

D

`-DeltaG = RT ln K_(c)`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaG = DeltaG + RTlnQ`
at eq. `DeltaG = 0` and `Q = K_(c)`
`:. -DeltaG^(@) = RTlnK_(c)`
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