The correct order of equivalent conductance at infinite dilution of `LiCl, NaCl` and `KCl` is:

Options

A. `LiCl gt NaCl gt KCl`
B. `KCl gt NaCl gt LiCl`
C. `NaCl gt KCl gt LiCl`
D. `LiCl gt KCl gt NaCl`

Explanation

To determine the correct order of equivalent conductance at infinite dilution for LiCl, NaCl, and KCl, we need to consider the ionic mobility of the cations (Li⁺, Na⁺, and K⁺) and their sizes. Here's a step-by-step solution:

### Step 1: Understand Equivalent Conductance
Equivalent conductance (Λ) at infinite dilution refers to the ability of ions to conduct electricity when they are completely dissociated in solution. It is influenced by the number of ions present and their mobility.

### Step 2: Analyze Ionic Mobility
Ionic mobility is the speed at which an ion moves through a solution under the influence of an electric field. It depends on the size of the ion; smaller ions tend to have higher mobility due to less hindrance from solvent molecules.

### Step 3: Compare the Sizes of Cations
The sizes of the cations in the compounds are as follows:
- Li⁺ (Lithium ion) - smallest
- Na⁺ (Sodium ion) - medium size
- K⁺ (Potassium ion) - largest

### Step 4: Relate Size to Mobility
Since smaller ions (like Li⁺) are more hydrated, they move slower compared to larger ions (like K⁺). Therefore, the order of ionic mobility from highest to lowest is:
1. K⁺ (highest mobility)
2. Na⁺ (medium mobility)
3. Li⁺ (lowest mobility)

### Step 5: Determine Equivalent Conductance Order
Since equivalent conductance is directly related to ionic mobility, we can conclude that:
- KCl will have the highest equivalent conductance due to K⁺.
- NaCl will have a medium equivalent conductance due to Na⁺.
- LiCl will have the lowest equivalent conductance due to Li⁺.

### Final Order
Thus, the correct order of equivalent conductance at infinite dilution is:
**KCl > NaCl > LiCl**

### Answer
The correct order of equivalent conductance at infinite dilution of LiCl, NaCl, and KCl is: **KCl > NaCl > LiCl** (Option B).

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