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Electrolysis of dilute aqueous NaCl solu...

Electrolysis of dilute aqueous `NaCl` solution was carried out by passing `10` milli-ampere current. The time required to liberate `0.01` mole of `H_(2)` gas at the cathode is :
(`1` faraday `= 96500 C mol^(-1)`)

A

`9.65 xx 10^(4)` sec

B

`19.3 xx 10^(4)` sec

C

`28.95 xx 10^(4)` sec

D

`38.6 xx 10^(4)` sec

Text Solution

Verified by Experts

The correct Answer is:
B
`(w)/(E) = (i xx T)/(96500)`
`0.01 xx 2 = (10 xx 10^(-3) xx t)/(96500)`
` t = 19.3 xx 10^(4)` sec
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