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Consider the following cell reaction : ...

Consider the following cell reaction :
`2Fe_(s) + O_(2(g)) + 4H_((aq.))^(+) rarr 2Fe_((aq.))^(2+) + 2H_(2)O_((l)), E^(@) = 1.67 V`
`At[Fe^(2+)] = 10^(-3)M, P(O_(2)) = 0.1 atm` and `pH = 3`, the cell potential at `25^(@)C` is:

A

`1.47 V`

B

`1.77 V`

C

`1.87 V`

D

`1.57 V`

Text Solution

Verified by Experts

The correct Answer is:
D
`2Fe_(s) + O_(2(g)) + 4H_((aq.))^(+) rarr 2Fe_((aq.))^(2+) + 2H_(2)O_((l))`
`n = 4` (no. of moles of electron involved)
From Nernst's equation,
`E_(cell) = E_(cell)^(@) - (0.059)/(n)log Q`
`= 1.67 - (0.0591)/(4)log'((10^(-3))^(2))/(0.1 xx (10^(-3))^(4))`
`= 1.67 xx 0.106`
`= 1.57 V`
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